Lemmara logoLemmaraWorked solution

0580/13 May/Jun 2026, Question 18: Zero and Negative Indices

Cambridge IGCSE Mathematics 0580 · Paper 13 (Core) · Non-calculator · 3 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

Find the cube root of 27, then express 5 to the power −1 as a decimal.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (a) · 1 mark

State the value of the cube root of 27.

  1. 13 × 3 × 3 = 27
  2. 2∛27 = 3

Answer3

Part (b) · 2 marks

Convert 5⁻¹ into decimal form.

  1. 15⁻¹ = 1/5
  2. 21/5 = 0.2

Answer0.2

Stuck on a step? Read the free lesson: Zero and Negative Indices

Practise more zero and negative indices questions

Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on zero and negative indices

Also searched as: 0580/13/M/J/26 · 0580_s26_qp_13 · 0580 s26 13 · question 18.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.