0580/13 Oct/Nov 2024, Question 23: The Sine Ratio
Cambridge IGCSE Mathematics 0580 · Paper 13 (Core) · Calculator · 2 marks
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The question, in short
Use the right-angled triangle with hypotenuse 9.7 cm and an angle of 42° to calculate the side x opposite that angle.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 2 marks
- 1sin 42° = x/9.7
- 2x = 9.7 × sin 42° = 6.490… ≈ 6.49
Answer6.49 or 6.490 to 6.491
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