WMA11/01 Jan 2020, Question 10: Sketching Cubics and Reciprocal Curves
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 1 (WMA11) · Calculator · 8 marks
The question, in short
Given cubic f(x) = (4x − 3)(x − 5)², draw its curve with axis intercepts, solve related equations, and work with the shifted curve g(x) = f(x + 1).
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Draw the graph of y = f(x), marking where it meets the x-axis and y-axis, including any touching point.
- 1The x³ coefficient is 4 > 0, so it is a positive cubic
- 2Roots: 4x − 3 = 0 gives x = 3/4 (crosses); (x − 5)² gives a repeated root at x = 5 (touches)
- 3At x = 0: y = (−3)(25) = −75
AnswerPositive cubic: rises from bottom left, crosses the y-axis at (0, −75), crosses the x-axis at (3/4, 0), reaches a maximum, then comes down to touch the x-axis at (5, 0) (a minimum) and rises again
Part (bi) · 1 mark
Solve f((1/4)x) = 0 to find the x values.
- 1f(¼x) = 0 when ¼x = 3/4 or ¼x = 5
- 2So x = 3 or x = 20
Answerx = 3, x = 20
Part (bii) · 1 mark
Determine the constant p so that y = f(x) + p goes through the origin.
- 1The curve meets the y-axis at (0, −75)
- 2Shifting up by 75 makes it pass through the origin, so p = 75
Answerp = 75
Part (ci) · 2 marks
Express g(x) = f(x + 1) in simplest form, factorised if preferred.
- 1g(x) = f(x + 1) = (4(x + 1) − 3)((x + 1) − 5)²
- 2= (4x + 1)(x − 4)²
Answerg(x) = (4x + 1)(x − 4)²
Part (cii) · 1 mark
Use your g(x) to find where curve C₂ meets the y-axis.
- 1Set x = 0 in g(x): (1)(−4)²
- 2= 16, so the y-intercept is 16
Answer16 (the point (0, 16))
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