WMA11/01 Jun 2023, Question 10: When a Line Meets, Touches or Misses a Curve
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 1 (WMA11) · Calculator · 10 marks
The question, in short
Sketch shows quadratic C and lines l₁, l₂; use given equations to find line equations, point P in terms of b, and the value of b.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 1 mark
Write the equation of line l₁ with gradient 1/2 passing through C's negative x-intercept.
- 1C meets the negative x-axis at x = −2, so l₁ passes through (−2, 0)
- 2Gradient 1/2: y = (1/2)(x + 2)
Answery = (1/2)(x + 2)
Part (aii) · 3 marks
Find the coordinates of point P where l₁ meets C, giving them in terms of b.
- 1Set −(1/4)(x + 2)(x − b) = (1/2)(x + 2)
- 2At P, x ≠ −2, so divide by (x + 2): −(1/4)(x − b) = 1/2
- 3x − b = −2, so x = b − 2
- 4y = (1/2)(b − 2 + 2) = b/2, so P is (b − 2, b/2)
AnswerP(b − 2, b/2)
Part (b) · 2 marks
Find an equation for l₂, perpendicular to l₁, through C's positive x-intercept, in terms of b.
- 1l₂ is perpendicular to l₁, so its gradient is −2
- 2C meets the positive x-axis at (b, 0)
- 3y = −2(x − b)
Answery = −2(x − b)
Part (c) · 2 marks
Given l₂ also passes through P, show its equation can be written as y = −2x + 5b/2 − 4.
- 1l₂ has gradient −2 and passes through P(b − 2, b/2)
- 2y − b/2 = −2(x − (b − 2)) = −2x + 2b − 4
- 3y = −2x + 5b/2 − 4
AnswerShown: line through P(b − 2, b/2) with gradient −2 is y − b/2 = −2(x − b + 2), giving y = −2x + 5b/2 − 4
Part (d) · 2 marks
Use the results to determine the numerical value of b.
- 1Both equations describe l₂: −2x + 2b = −2x + 5b/2 − 4
- 22b = 5b/2 − 4, so b/2 = 4
- 3b = 8
Answerb = 8
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