WMA12/01 Oct 2022, Question 10: Solving Exponential and Log Equations
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 2 (WMA12) · Calculator · 7 marks
The question, in short
Using a = log₂3, express two logarithmic quantities in terms of a, then solve an equation in x involving 3ˣ and 2ˣ⁺⁴, giving x in terms of a.
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Part (ia) · 1 mark
Express log₂9 using a only, in its simplest form.
- 1log₂9 = log₂3²
- 2= 2log₂3 = 2a
Answer2a
Part (ib) · 2 marks
Express log₂(√3/16) in terms of a, simplified as far as possible.
- 1log₂(√3/16) = log₂√3 − log₂16
- 2= (1/2)log₂3 − 4
- 3= (1/2)a − 4
Answer(1/2)a − 4
Part (ii) · 4 marks
Find x satisfying 3ˣ × 2ˣ⁺⁴ = 6, with the answer in simplest form involving a.
- 1Take log₂ of both sides: log₂3ˣ + log₂2ˣ⁺⁴ = log₂6
- 2x log₂3 + (x + 4) = log₂2 + log₂3
- 3ax + x + 4 = 1 + a
- 4x(a + 1) = a − 3
- 5x = (a − 3)/(a + 1)
Answerx = (a − 3)/(a + 1)
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