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WMA12/01 Oct 2024, Question 11: Proof by Exhaustion and Counter-example

Pearson Edexcel International AS Level Mathematics · Pure Mathematics 2 (WMA12) · Calculator · 6 marks

The question, in short

Show the prime claim fails using a counter example, then prove by exhaustion that m² − 1 is divisible by 3 when integer m is not a multiple of 3.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (i) · 2 marks

Give one prime value of n for which 3ⁿ + 2 is not prime, showing the resulting number is composite.

  1. 1Try the prime n = 5
  2. 23⁵ + 2 = 243 + 2 = 245
  3. 3245 = 5 × 49, so 245 is not prime
  4. 4So the statement is false

AnswerCounter-example: n = 5 is prime but 3⁵ + 2 = 245 = 5 × 49 is not prime, so the statement is false

Part (ii) · 4 marks

Consider the two cases of m not divisible by 3, showing in each that m² − 1 is divisible by 3.

  1. 1If m is not divisible by 3, then m = 3k + 1 or m = 3k + 2 for some integer k
  2. 2m = 3k + 1: m² − 1 = 9k² + 6k + 1 − 1 = 9k² + 6k = 3(3k² + 2k)
  3. 3m = 3k + 2: m² − 1 = 9k² + 12k + 4 − 1 = 9k² + 12k + 3 = 3(3k² + 4k + 1)
  4. 4Both are multiples of 3, so m² − 1 is divisible by 3 whenever m is not divisible by 3

AnswerShown: m = 3k + 1 gives m² − 1 = 3(3k² + 2k); m = 3k + 2 gives m² − 1 = 3(3k² + 4k + 1); both are multiples of 3

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Also searched as: WMA12 October 2024 · WMA12/01 · wma12 oct24 · IAS Maths Pure Mathematics 2 October 2024 · question 11.
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