0580/22 Feb/Mar 2021, Question 24: Stationary Points and Turning Points
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 5 marks
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The question, in short
Find the coordinates of both stationary points of the curve y = x³ − 2x² + 5.
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Solution · 5 marks
- 1dy/dx = 3x² − 4x
- 23x² − 4x = 0 so x(3x − 4) = 0
- 3x = 0 or x = 4/3
- 4x = 0: y = 5
- 5x = 4/3: y = 64/27 − 32/9 + 5 = 103/27
- 6Stationary points (0, 5) and (4/3, 103/27)
Answer(0, 5) and (4/3, 103/27)
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Also searched as: 0580/22/F/M/21 · 0580_m21_qp_22 · 0580 m21 22 · question 24.
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