0580/12 Feb/Mar 2024, Question 6: Factors and Multiples
Cambridge IGCSE Mathematics 0580 · Paper 12 (Core) · Calculator · 3 marks
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The question, in short
From a given list, identify multiples of 11, then apply Zaid's alternating digit method to show that 918 271 937 is a multiple of 11.
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Part (a) · 1 mark
From the list 34, 55, 76, 83, 111, 121, write down every number that is a multiple of 11.
- 155 = 5 × 11 and 121 = 11 × 11
- 2Multiples of 11: 55, 121
Answer55 121
Part (b) · 2 marks
Using Zaid's method, alternately subtract and add the digits of 918 271 937 and check the result to show it is a multiple of 11.
- 19 − 1 + 8 − 2 + 7 − 1 + 9 − 3 + 7 = 33
- 233 = 3 × 11, a multiple of 11
- 3So 918 271 937 is a multiple of 11
Answer9 − 1 + 8 − 2 + 7 − 1 + 9 − 3 + 7 = 33 = 3 × 11
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