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0580/41 May/Jun 2021, Question 1: Everyday Money Problems

Cambridge IGCSE Mathematics 0580 · Paper 41 (Extended) · Calculator · 10 marks

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The question, in short

Taxi fare questions: compute a fare from distance and time, verify a journey time, split a total distance in a given ratio, and reverse a 45% increase.

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Part (ai) · 2 marks

Find the total fare for a 32 km journey lasting 30 minutes using 0.50 per km plus 0.40 per minute.

  1. 1Cost = 32 × 0.50 + 30 × 0.40
  2. 2= 16 + 12 = $28

Answer28

Part (aii) · 3 marks

For a 100 km journey costing $98, show the journey time equals 2 hours.

  1. 1Distance cost = 100 × 0.5 = 50
  2. 2Time cost = 98 − 50 = 48
  3. 3Time = 48 ÷ 0.4 = 120 minutes = 2 hours

Answer98 − 100 × 0.5 = 48 48 ÷ 0.4 = 120 minutes = 2 hours

Part (b) · 3 marks

Three drivers cover 8190 km in the ratio 5 : 2 : 7; find each driver's distance.

  1. 11 part = 8190 ÷ (5 + 2 + 7) = 8190 ÷ 14 = 585
  2. 25 × 585 = 2925, 2 × 585 = 1170, 7 × 585 = 4095
  3. 32925 km, 1170 km, 4095 km

AnswerDriver 1: 2925 km, Driver 2: 1170 km, Driver 3: 4095 km

Part (c) · 2 marks

A journey costs $84.10 after a 45% midnight increase; find its cost before midnight.

  1. 1Cost before × 1.45 = 84.10
  2. 2Cost before = 84.10 ÷ 1.45 = $58

Answer58

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Also searched as: 0580/41/M/J/21 · 0580_s21_qp_41 · 0580 s21 41 · question 1.
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