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0580/33 May/Jun 2022, Question 6: Averages from Frequency Tables

Cambridge IGCSE Mathematics 0580 · Paper 33 (Core) · Calculator · 11 marks

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The question, in short

Using a bar chart of customers at 30 tables at 7 pm, find the mode, range and mean, compare with 1 pm data, and complete a pie chart table and chart for 270 meals.

Summarised in our own words. Use the official paper for the exact wording and the diagram.

Part (ai) · 1 mark

Write down the mode of the number of customers per table at 7 pm.

  1. 1Tallest bar is 4 customers (9 tables)
  2. 2Mode = 4

Answer4

Part (aii) · 1 mark

Find the range of the number of customers per table at 7 pm.

  1. 1Range = 6 − 1 = 5

Answer5

Part (aiii) · 3 marks

Calculate the mean number of customers per table at 7 pm.

  1. 1Total customers = 1×2 + 2×7 + 3×3 + 4×9 + 5×4 + 6×5
  2. 2= 2 + 14 + 9 + 36 + 20 + 30 = 111
  3. 3Mean = 111 ÷ 30 = 3.7

Answer3.7

Part (b) · 2 marks

Write down two comments comparing the 7 pm results with the 1 pm results.

  1. 1Mode at 1 pm is 2, mode at 7 pm is 4: more customers per table at 7 pm
  2. 2Range at 1 pm is 4 − 1 = 3, range at 7 pm is 5: 7 pm results are more spread out
  3. 3(Also: 1 pm total 8 + 26 + 15 + 16 = 65 customers, 7 pm total 111)

AnswerTwo correct comments with different types of comment

Part (ci) · 2 marks

Complete the table by finding the missing pie chart sector angles for Meat and Fish.

  1. 11 meal = 360 ÷ 270 = 4/3°
  2. 2Meat = 117 × 4/3 = 156°
  3. 3Fish = 99 × 4/3 = 132°

AnswerMeat 156°, Fish 132°

Part (cii) · 2 marks

Complete the pie chart using the sector angles for Meat, Fish and Vegetarian.

  1. 1From the vertical radius, measure a 156° sector (Meat)
  2. 2Next to it a 132° sector (Fish)
  3. 3The remaining sector is 72° (Vegetarian); label all three

AnswerCorrect pie chart drawn

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Also searched as: 0580/33/M/J/22 · 0580_s22_qp_33 · 0580 s22 33 · question 6.
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