0580/22 May/Jun 2023, Question 16: Recurring Decimals
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 3 marks
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The question, in short
Convert the recurring decimal 0.6212121... (with 6 non-recurring and 21 recurring) into a fraction in simplest form, showing all working.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 3 marks
- 1x = 0.62121…
- 21000x = 621.2121… and 10x = 6.2121…
- 3990x = 621.2121… − 6.2121… = 615
- 4x = 615/990 = 41/66
Answer41/66
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