0580/33 May/Jun 2023, Question 4: Speed, Distance and Time

Part (ai) · 1 mark

Read off the departure time from A on the graph's time axis.

1. 1The line starts at distance 0 at 10 20
2. 210 20

Answer10 20

Part (aii) · 1 mark

Find the journey duration from A to B in minutes using the graph.

1. 1The boat reaches B (6 km) at 11 00
2. 211 00 − 10 20 = 40 minutes

Answer40

Part (aiii) · 2 marks

Add a 20-minute stop at B then a constant 8 km/h leg to C at 18 km.

1. 1Stay at B: horizontal line from (11 00, 6) to (11 20, 6)
2. 2B to C: 18 − 6 = 12 km at 8 km/h takes 12 ÷ 8 = 1.5 h
3. 3Arrives at 11 20 + 1 h 30 min = 12 50
4. 4Ruled line from (11 20, 6) to (12 50, 18)

AnswerRuled lines from (11 00, 6) to (11 20, 6) and (11 20, 6) to (12 50, 18)

Part (aiv) · 3 marks

Calculate average speed in km/h over the entire A to C trip.

1. 1Total time = 10 20 to 12 50 = 2 h 30 min = 2.5 h
2. 2Average speed = 18 ÷ 2.5 = 7.2 km/h

Answer7.2

Part (bi) · 1 mark

Measure the bearing of Y from X on the scale drawing.

1. 1Measure clockwise from the North line at X to the line XY
2. 2Bearing = 065°

Answer065 (accept 063 to 067)

Part (bii) · 2 marks

Mark point B on the drawing, 52 km from X and 80 km from Y using 1 cm to 8 km.

1. 152 ÷ 8 = 6.5 cm and 80 ÷ 8 = 10 cm
2. 2Draw an arc of radius 6.5 cm centre X and an arc of radius 10 cm centre Y
3. 3B is where the arcs cross (in the sea)

AnswerB correctly marked 6.5 cm from X and 10 cm from Y

Part (biii) · 2 marks

Work out the reverse bearing of X from S given S lies on 284° from X.

1. 1Bearing of X from S = 284 − 180
2. 2= 104°

Answer104

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