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0580/41 May/Jun 2023, Question 1: Currency Conversions

Cambridge IGCSE Mathematics 0580 · Paper 41 (Extended) · Calculator · 13 marks

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The question, in short

Orchard with 1250 trees in ratio 12:9:4; work out apple tree count, total fruit mass in tonnes, previous pear mass, trees after storm loss, and Paulo's pear costs and change.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (ai) · 2 marks

Find the number of apple trees from 1250 trees split in the ratio 12:9:4.

  1. 112 + 9 + 4 = 25 parts
  2. 21 part = 1250 ÷ 25 = 50 trees
  3. 3Apple trees = 12 × 50 = 600

Answer600

Part (aii) · 2 marks

Using mean 64 kg per tree, find total fruit mass in tonnes (1 tonne = 1000 kg).

  1. 1Total mass = 1250 × 64 = 80 000 kg
  2. 280 000 ÷ 1000 = 80 tonnes

Answer80

Part (aiii) · 2 marks

Mean pear mass 54 kg per tree is a 10% decrease; find the previous year's mean mass per tree.

  1. 1Last year = 90% of the year before: x × (1 − 10/100) = 54
  2. 20.9x = 54
  3. 3x = 54 ÷ 0.9 = 60 kg

Answer60

Part (aiv) · 2 marks

After losing 1/5 of all trees in a storm, find how many trees remain.

  1. 1Trees lost = 1250 ÷ 5 = 250
  2. 2Trees remaining = 1250 − 250 = 1000

Answer1000

Part (bi) · 2 marks

Paulo buys 12 pears at $0.54 each and pays with $10; find his change.

  1. 1Cost = 12 × 0.54 = $6.48
  2. 2Change = 10 − 6.48 = $3.52

Answer3.52

Part (bii) · 3 marks

With $1 = 0.826 euros, find how much more each pear costs in euros than in dollars, in dollars to nearest cent.

  1. 1Euro price in dollars = 0.51 ÷ 0.826 = $0.6174…
  2. 2Difference = 0.6174… − 0.54 = 0.0774…
  3. 3≈ $0.08 (to the nearest cent)

Answer0.08

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Also searched as: 0580/41/M/J/23 · 0580_s23_qp_41 · 0580 s23 41 · question 1.
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