0580/42 May/Jun 2023, Question 10: Trigonometry in 3D: Cuboids
Cambridge IGCSE Mathematics 0580 · Paper 42 (Extended) · Calculator · 8 marks
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The question, in short
Diagonals of cuboids: find the base side x from a 3D diagonal of 28 cm and height 20 cm, then a lower-bound angle between a diagonal and the base using rounded lengths.
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Part (a) · 4 marks
Square-based cuboid, height 20 cm, space diagonal 28 cm: find the side x.
- 1AC² = AG² − CG² = 28² − 20² = 784 − 400 = 384
- 2AC² = x² + x², so 2x² = 384
- 3x² = 192
- 4x = √192 = 13.85… ≈ 13.9
Answer13.9 or 13.85 to 13.86
Part (b) · 4 marks
Lengths 30 cm and 37 cm to the nearest cm: lower bound of the angle between the diagonal and the base.
- 1The angle between KR and the base is angle RKM, with sin RKM = MR/KR
- 2Lower bound: smallest MR and largest KR
- 3sin RKM = (30 − 0.5)/(37 + 0.5) = 29.5/37.5
- 4Angle = sin⁻¹(0.7866…) = 51.87…° ≈ 51.9°
Answer51.9 or 51.87 to 51.88
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Also searched as: 0580/42/M/J/23 · 0580_s23_qp_42 · 0580 s23 42 · question 10.
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