0580/23 May/Jun 2024, Question 21: Recurring Decimals
Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Calculator · 2 marks
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The question, in short
Convert the recurring decimal 0.41 with the 1 repeating into a fraction in simplest form, showing all working.
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Solution · 2 marks
- 1Let x = 0.4111…
- 2100x = 41.111… and 10x = 4.111…
- 390x = 41.111… − 4.111… = 37
- 4x = 37/90
Answer37/90
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