0580/31 May/Jun 2026, Question 13: Order of Operations
Cambridge IGCSE Mathematics 0580 · Paper 31 (Core) · Calculator · 2 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Insert one pair of brackets into each of two calculations so that the stated result is obtained.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Place one pair of brackets in 10 + 12 − 8 × 5 so it equals 30.
- 1(12 − 8) × 5 = 4 × 5 = 20
- 210 + 20 = 30
Answer10 + (12 − 8) × 5 = 30
Part (b) · 1 mark
Place one pair of brackets in 10 + 20 × 7 ÷ 5 so it equals 30.
- 110 + 20 × 7 = 10 + 140 = 150
- 2150 ÷ 5 = 30
Answer(10 + 20 × 7) ÷ 5 = 30
Stuck on a step? Read the free lesson: Order of Operations
Practise more order of operations questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on order of operations
Also searched as: 0580/31/M/J/26 · 0580_s26_qp_31 · 0580 s26 31 · question 13.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.