0580/31 May/Jun 2026, Question 25: The nth Term of a Linear Sequence
Cambridge IGCSE Mathematics 0580 · Paper 31 (Core) · Calculator · 6 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Sequence starts 3, 7, 11, 15. Find its nth term, show 603 belongs to it, and for a different sequence with nth term n² − 6 find the first three terms.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (ai) · 2 marks
Find the nth term of the sequence whose first four terms are 3, 7, 11, 15.
- 1Common difference = 4, so 4n
- 2When n = 1, 4n = 4 and the term is 3, so subtract 1
- 3nth term = 4n − 1
Answer4n − 1
Part (aii) · 2 marks
Show that 603 is a term of the sequence with first terms 3, 7, 11, 15.
- 14n − 1 = 603
- 24n = 604
- 3n = 151, which is a whole number, so 603 is the 151st term
Answer4n − 1 = 603 gives n = 151, a whole number, so 603 is a term
Part (b) · 2 marks
For the sequence with nth term n² − 6, find the first three terms.
- 1n = 1: 1² − 6 = −5
- 2n = 2: 2² − 6 = −2
- 3n = 3: 3² − 6 = 3
Answer−5, −2, 3
Stuck on a step? Read the free lesson: The nth Term of a Linear Sequence
Practise more the nth term of a linear sequence questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on the nth term of a linear sequence
Also searched as: 0580/31/M/J/26 · 0580_s26_qp_31 · 0580 s26 31 · question 25.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.