0580/22 Oct/Nov 2021, Question 15: The Equation y = mx + c
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 4 marks
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The question, in short
Find the equation of the line through A (3, 16) and B (8, 31) in y = mx + c form, and the gradient of a line perpendicular to y = 0.5x − 11.
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Part (a) · 3 marks
Find the equation of the line through (3, 16) and (8, 31), giving it as y = mx + c.
- 1Gradient = (31 − 16)/(8 − 3) = 15/5 = 3
- 216 = 3 × 3 + c, so c = 7
- 3y = 3x + 7
Answery = 3x + 7
Part (b) · 1 mark
Find the gradient of a line perpendicular to the line with equation y = 0.5x − 11.
- 1Gradient of CD = 0.5
- 2Perpendicular gradient = −1 ÷ 0.5 = −2
Answer−2
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Also searched as: 0580/22/O/N/21 · 0580_w21_qp_22 · 0580 w21 22 · question 15.
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