0580/33 Oct/Nov 2021, Question 1: Speed, Distance and Time
Cambridge IGCSE Mathematics 0580 · Paper 33 (Core) · Calculator · 16 marks
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The question, in short
Solve travel and park problems: flight arrival time across time zones, average speed, car hire cost formula, missing probability, rounding and standard form for 4986, tax on $17.50 at 8%, and scale-drawing distance and bearing work.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Given departure 15 40 London time and an 11 h 15 min flight, find the Los Angeles arrival time, with the city 8 hours behind London.
- 115 40 + 11 h 15 min = 02 55 (London time)
- 202 55 − 8 h = 18 55 (Los Angeles time)
Answer18 55
Part (aii) · 3 marks
Using a flight distance of 8760 km and the time from part (a)(i), work out the plane's average speed.
- 111 h 15 min = 11.25 h
- 2Speed = 8760 ÷ 11.25
- 3= 778.66… ≈ 779 km/h
Answer779 or 778.6 to 778.7
Part (bi) · 2 marks
Car hire costs $56 daily plus a fixed $436; give a formula for C dollars when hiring for d days.
- 1Cost for d days = 56d
- 2Add the fixed cost: C = 56d + 436
AnswerC = 56d + 436
Part (bii) · 2 marks
Four car colours have probabilities 0.17, 0.24, blank and 0.3; find the missing probability to finish the table.
- 1Probabilities sum to 1
- 21 − (0.17 + 0.24 + 0.3) = 1 − 0.71
- 3Black = 0.29
Answer0.29
Part (ci) · 1 mark
Round the park area 4986 km² to the nearest hundred.
- 14986 lies between 4900 and 5000
- 2Nearer to 5000
Answer5000
Part (cii) · 1 mark
Express 4986 in standard form.
- 14986 = 4.986 × 1000
- 2= 4.986 × 10³
Answer4.986 × 10³
Part (d) · 1 mark
Find the tax amount on a park ticket priced at $17.50 with 8% tax added.
- 18% of 17.50 = 0.08 × 17.50
- 2= $1.40
Answer1.40
Part (ei) · 2 marks
Using the scale where 1 cm represents 5 km, calculate the real distance between points A and B on the drawing.
- 1Measure AB on the drawing: 7 cm
- 27 × 5 = 35 km
Answer35 (accept 34 to 36)
Part (eii) · 2 marks
Mark point C on the scale drawing, 20 km from A on a bearing of 072°.
- 120 km ÷ 5 = 4 cm on the drawing
- 2Place the protractor at A, measure 72° clockwise from North
- 3Mark C 4 cm from A along this line
AnswerC marked 4 cm from A on a bearing of 072°
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