0580/33 Oct/Nov 2023, Question 1: Compound Interest
Cambridge IGCSE Mathematics 0580 · Paper 33 (Core) · Calculator · 12 marks
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The question, in short
Work through a restaurant bill, fractions and percentages, compound interest, and a dollars-to-Swiss-francs conversion graph, finding missing values and explaining a graph method.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Find the missing soup price so the listed items add to the total of $25.40.
- 113.30 + 4.80 + 3.81 = 21.91
- 2Soup = 25.40 − 21.91 = $3.49
Answer3.49
Part (aii) · 1 mark
Express the drinks cost of $3.81 as a percentage of the $25.40 total.
- 13.81/25.40 × 100 = 15%
Answer15
Part (bi) · 1 mark
Calculate 2/5 of $2400.
- 12400 ÷ 5 = 480
- 22/5 of $2400 = 480 × 2 = $960
Answer960
Part (bii) · 2 marks
Reduce $3450 by 18%.
- 118% of 3450 = 0.18 × 3450 = 621
- 23450 − 621 = $2829 (or 3450 × 0.82 = 2829)
Answer2829
Part (c) · 3 marks
Find the value after 5 years of $14000 invested at 1.6% yearly compound interest, to the nearest dollar.
- 1Value = 14000 × (1 + 1.6/100)⁵
- 2= 14000 × 1.016⁵ = 15156.4…
- 3≈ $15156 to the nearest dollar
Answer15156
Part (dia) · 1 mark
Use the conversion graph to convert $80 into Swiss francs.
- 1Go up from $80 on the Dollars axis to the line, then across to the Swiss francs axis
- 2$80 = 72 Swiss francs
Answer72
Part (dib) · 1 mark
Use the conversion graph to convert 108 Swiss francs into dollars.
- 1Go across from 108 on the Swiss francs axis to the line, then down to the Dollars axis
- 2108 Swiss francs = $120
Answer120
Part (dii) · 1 mark
Describe how the graph can be used to convert $360, which is beyond its scale.
- 1$360 is off the graph, so split it into values on the graph: 360 = 200 + 160
- 2From the graph, $200 = 180 francs and $160 = 144 francs
- 3Add: $360 = 180 + 144 = 324 Swiss francs
AnswerCorrect explanation, using any correct combination of values between 0 and 200 to reach 360
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Also searched as: 0580/33/O/N/23 · 0580_w23_qp_33 · 0580 w23 33 · question 1.
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