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0580/43 Oct/Nov 2024, Question 5: Speed, Distance and Time

Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 8 marks

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The question, in short

Three-part speed problem: convert a 100 m run in 15 seconds to km/h, combine two runs into an overall average speed, and derive a time in seconds for a train of length p through a station of length q at v km/h.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (a) · 2 marks

Work out the average speed in kilometres per hour for a 100 m run completed in 15 seconds.

  1. 1Speed = 100 ÷ 15 = 6.66... m/s
  2. 26.66... × 3600 ÷ 1000 = 24 km/h

Answer24

Part (b) · 3 marks

Find the overall average speed for a 45 minute run at 9.5 km/h followed by 8.1 km at 7.5 km/h.

  1. 1First distance = 9.5 × 45/60 = 7.125 km
  2. 2Second time = 8.1 ÷ 7.5 = 1.08 h
  3. 3Total distance = 7.125 + 8.1 = 15.225 km, total time = 0.75 + 1.08 = 1.83 h
  4. 4Average speed = 15.225 ÷ 1.83 = 8.32 km/h

Answer8.32 or 8.319 to 8.320

Part (c) · 3 marks

Give an expression in seconds, using p, q and v, for how long the train takes to clear the station completely.

  1. 1Distance to travel = (p + q) m
  2. 2Speed = v × 1000/3600 = 5v/18 m/s
  3. 3Time = (p + q) ÷ (5v/18)
  4. 4= 18(p + q)/(5v) seconds

Answer18(p + q)/(5v)

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Also searched as: 0580/43/O/N/24 · 0580_w24_qp_43 · 0580 w24 43 · question 5.
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