0580/21 Oct/Nov 2025, Question 11: Recurring Decimals
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Non-calculator · 2 marks
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The question, in short
Convert the recurring decimal 0.242424... to a fraction and reduce it to simplest form.
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Solution · 2 marks
- 1x = 0.2424…, so 100x = 24.2424…
- 2100x − x = 24.24… − 0.24…, so 99x = 24
- 3x = 24/99 = 8/33
Answer8/33
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