0606/13 May/Jun 2026, Question 2: Arithmetic Progressions in Problems
Cambridge IGCSE Additional Mathematics 0606 · Paper 13 (Non-calculator) · Non-calculator · 5 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Given an arithmetic progression with nonzero first term a and nonzero common difference d, use the two stated conditions about the 6th and 11th terms and the first six terms to determine a and d.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 5 marks
- 1a + 5d + a + 10d = 0, so 2a + 15d = 0
- 2(6/2)(2a + 5d) = −30, so 2a + 5d = −10
- 3Subtract: 10d = 10, d = 1
- 42a = −15, a = −15/2
Answerd = 1, a = −15/2
Stuck on a step? Read the free lesson: Arithmetic Progressions in Problems
Practise more arithmetic progressions in problems questions
Real 0606 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on arithmetic progressions in problems
Also searched as: 0606/13/M/J/26 · 0606_s26_qp_13 · 0606 s26 13 · question 2.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.