0606/21 May/Jun 2026, Question 6: Permutations: Counting Arrangements
Cambridge IGCSE Additional Mathematics 0606 · Paper 21 (Calculator) · Calculator · 3 marks
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The question, in short
Count 5-digit numbers using distinct digits from 0 to 9 that exceed 40 000 and are divisible by 5.
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Solution · 3 marks
- 1First digit 4–9, last digit 0 or 5
- 2Last digit 0: first digit 4, 5, 6, 7, 8 or 9 (6 ways): 6 × 8 × 7 × 6 = 2016
- 3Last digit 5: first digit 4, 6, 7, 8 or 9 (5 ways): 5 × 8 × 7 × 6 = 1680
- 4Total = 2016 + 1680 = 3696
Answer3696
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