0606/12 Oct/Nov 2025, Question 13: Trig Identities and Proofs
Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 4 marks
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The question, in short
Given x = 2 − 3 sin θ and y = 3 cot²θ for −1 ≤ x ≤ 1, express y in terms of x.
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Solution · 4 marks
- 1sin θ = (2 − x)/3
- 2y = 3 cos²θ/sin²θ = 3(1 − sin²θ)/sin²θ
- 3= 3(1/sin²θ − 1)
- 4y = 3(9/(2 − x)² − 1)
Answery = 3(9/(2 − x)² − 1)
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Also searched as: 0606/12/O/N/25 · 0606_w25_qp_12 · 0606 w25 12 · question 13.
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