4024/11 May/Jun 2020, Question 22: Choosing the Right Trigonometric Ratio
Cambridge O Level Mathematics 4024 · Paper 11 (Non-calculator) · Non-calculator · 1 mark
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The question, in short
Given that m = 141 solves sin m° = 0.63, find the other solution for 0 < m < 90, rounded to the nearest whole number.
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Solution · 1 mark
- 1sin m° = sin(180 − m)°
- 2m = 180 − 141 = 39
- 3(Check: sin⁻¹ 0.63 = 39.05… ≈ 39)
Answer39
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