4024/21 May/Jun 2020, Question 6: Plotting Curves from a Table of Values
Cambridge O Level Mathematics 4024 · Paper 21 (Calculator) · Calculator · 12 marks
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The question, in short
Complete a table for y = x³/4 − x + 1, plot its graph on the grid for −3 ≤ x ≤ 3, add the line y = 1/3 x + 1, read off intersection x-values, and find integers A and B in Ax³ = Bx; then match three given quadratic equations to three sketches.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 1 mark
Use the rule y = x³/4 − x + 1 to work out the missing y-value when x = 3.
- 1x = 3: y = 27/4 − 3 + 1
- 2= 6.75 − 2 = 4.75
Answer4.75
Part (aii) · 3 marks
Plot the completed points and draw a smooth curve for y = x³/4 − x + 1 between x = −3 and x = 3.
- 1Plot (−3, −2.75), (−2, 1), (−1, 1.75), (0, 1), (1, 0.25), (2, 1), (3, 4.75)
- 2Join with a smooth cubic curve through all seven points (maximum near x = −1, minimum near x = 1)
AnswerCorrect curve
Part (aiiia) · 2 marks
- 1y-intercept is 1, gradient 1/3
- 2Points: (−3, 0), (0, 1), (3, 2)
- 3Rule a straight line through them
AnswerRuled line through (0, 1), gradient 1/3
Part (aiiib) · 2 marks
From your graphs, state every x-value where the straight line meets the cubic curve.
- 1Read off the x-coordinates where the line meets the curve
- 2x ≈ −2.3, x = 0, x ≈ 2.3
Answer−2.5 to −2.1, 0, 2.1 to 2.5
Part (aiiic) · 2 marks
Rearrange the intersection condition to the form Ax³ = Bx and give the integer values of A and B.
- 11/3 x + 1 = x³/4 − x + 1
- 2x³/4 = x + 1/3 x = 4/3 x
- 3Multiply by 12: 3x³ = 16x
- 4A = 3, B = 16
AnswerA = 3, B = 16
Part (b) · 2 marks
Match each of the three U-shaped sketches to the correct equation from the four listed, writing it beneath the graph.
- 1Minimum at O: y = 2x²
- 2Symmetrical with y-intercept below O: y = 2x² − 2
- 3Through O with roots 0 and 2 (minimum to the right): y = x² − 2x
Answery = 2x², y = 2x² − 2, y = x² − 2x
Stuck on a step? Read the free lesson: Plotting Curves from a Table of Values
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