4024/11 May/Jun 2021, Question 6: Prime Factorization
Cambridge O Level Mathematics 4024 · Paper 11 (Non-calculator) · Non-calculator · 3 marks
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The question, in short
Express 308 using only prime factors, then determine the greatest common divisor shared by 308 and 66.
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Part (a) · 2 marks
Break down 308 into a multiplication of primes.
- 1308 = 2 × 154 = 2 × 2 × 77 = 2 × 2 × 7 × 11
- 2308 = 2² × 7 × 11
Answer2² × 7 × 11
Part (b) · 1 mark
Work out the largest number dividing both 308 and 66 exactly.
- 1308 = 2² × 7 × 11
- 266 = 2 × 3 × 11
- 3Common prime factors: 2 and 11, so HCF = 2 × 11 = 22
Answer22
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Also searched as: 4024/11/M/J/21 · 4024_s21_qp_11 · 4024 s21 11 · question 6.
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