4024/22 May/Jun 2022, Question 4: Pythagoras' Theorem
Cambridge O Level Mathematics 4024 · Paper 22 (Calculator) · Calculator · 14 marks
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The question, in short
Work with a pentagon whose side lengths are given in centimetres, a sphere of volume 2572 cm³, and a cuboid measuring 2 cm by 6 cm by 22.5 cm.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Work out the area of the pentagon from the diagram, giving the result in cm².
- 1Split into a 4 × 15 rectangle and a triangle
- 2Rectangle = 4 × 15 = 60
- 3Triangle: base 12 − 4 = 8, height 15 − 9 = 6, area = 1/2 × 8 × 6 = 24
- 4Area = 60 + 24 = 84 cm²
Answer84
Part (aii) · 3 marks
Work out the total distance around the pentagon, in centimetres.
- 1Sloping side = √(8² + 6²)
- 2= √100 = 10
- 3Perimeter = 12 + 15 + 4 + 9 + 10 = 50 cm
Answer50
Part (b) · 3 marks
Use the sphere volume formula to determine the radius of a sphere whose volume is 2572 cm³.
- 14/3 πr³ = 2572
- 2r³ = (2572 × 3)/(4π) = 614.0…
- 3r = ∛614.0… = 8.498…
- 4r = 8.50 cm
Answer8.5 or 8.49 to 8.50
Part (ci) · 3 marks
Work out the total surface area of the 2 cm by 6 cm by 22.5 cm cuboid.
- 1Face areas: 2 × 6 = 12, 2 × 22.5 = 45, 6 × 22.5 = 135
- 2Surface area = 2 × (12 + 45 + 135)
- 3= 2 × 192 = 384 cm²
Answer384
Part (cii) · 3 marks
For a cube of edge x cm with the same surface area as the cuboid, write an equation in x and solve it, showing your working.
- 1A cube has 6 square faces: 6x² = 384
- 2x² = 64
- 3x = 8 cm
Answer8
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