4024/22 Oct/Nov 2021, Question 3: Plotting Curves from a Table of Values
Cambridge O Level Mathematics 4024 · Paper 22 (Calculator) · Calculator · 11 marks
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The question, in short
Complete a table for y = x³/2 − 3x − 1, plot its graph for −3 ≤ x ≤ 3, then use it to reason about solutions and a line through (1, 1) and (−2, −1).
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 1 mark
Fill in the missing y-value in the table for y = x³/2 − 3x − 1 at the given x values.
- 1x = −3: (−3)³/2 − 3 × (−3) − 1 = −13.5 + 9 − 1 = −5.5
Answer−5.5 or −5 1/2 or −11/2
Part (b) · 3 marks
Plot the curve y = x³/2 − 3x − 1 on the grid for x from −3 to 3.
- 1Plot (−3, −5.5), (−2, 1), (−1, 1.5), (0, −1), (1, −3.5), (2, −3), (3, 3.5)
- 2Join with a smooth curve
AnswerCorrect smooth curve
Part (c) · 2 marks
Using the drawn graph, justify why x³ − 6x − 2 = 6 has exactly one solution.
- 1x³ − 6x − 2 = 6 → ÷ 2: x³/2 − 3x − 1 = 3
- 2The line y = 3 meets the curve only once, so there is only one solution
AnswerLine y = 3 only intersects the graph once
Part (di) · 1 mark
Draw line L through (1, 1) and (−2, −1) on the grid.
- 1Plot (1, 1) and (−2, −1) and rule a straight line through them across the grid
AnswerRuled line through (1, 1) and (−2, −1)
Part (dii) · 2 marks
Calculate the gradient of line L.
- 1Gradient = (1 − (−1))/(1 − (−2)) = 2/3
Answer2/3
Part (diii) · 2 marks
Determine the x-coordinates where line L meets the curve y = x³/2 − 3x − 1.
- 1Read the x-coordinates where line L crosses the curve
- 2Line L: y = 2/3 x + 1/3; exactly, 3x³ − 22x − 8 = 0
- 3x ≈ −2.5, x ≈ −0.37, x ≈ 2.87
Answer−2.6 to −2.4, −0.45 to −0.3, 2.8 to 2.95
Stuck on a step? Read the free lesson: Plotting Curves from a Table of Values
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Also searched as: 4024/22/O/N/21 · 4024_w21_qp_22 · 4024 w21 22 · question 3.
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