4MA1/1F Jun 2018, Question 16: Solving Linear Equations
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1F (Foundation) · Calculator · 9 marks
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The question, in short
Simplify two index expressions, solve a linear equation showing working, then factorise a quadratic and use the result to solve the related equation.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Simplify y⁵ × y⁹.
- 1y⁵ × y⁹ = y^(5+9) = y¹⁴
Answery¹⁴
Part (b) · 2 marks
Simplify (2m³)⁴.
- 1Raise each part to the power 4: 2⁴ × (m³)⁴
- 22⁴ = 16, and (m³)⁴ = m¹² (multiply the powers 3 × 4).
- 3Answer: 16m¹²
Answer16m¹²
Part (c) · 3 marks
Solve 5(x + 3) = 3x − 4, showing clear algebraic working.
- 15(x + 3) = 3x − 4
- 25x + 15 = 3x − 4
- 35x − 3x = −4 − 15
- 42x = −19
- 5x = −19/2
Answer−19/2
Part (di) · 2 marks
Factorise x² + 2x − 24.
- 1Find two numbers that multiply to −24 and add to 2: 6 and −4
- 2(x − 4)(x + 6)
Answer(x − 4)(x + 6)
Part (dii) · 1 mark
Using your factorisation, solve x² + 2x − 24 = 0.
- 1(x − 4)(x + 6) = 0
- 2x − 4 = 0 or x + 6 = 0
- 3x = 4 or x = −6
Answer4, −6
Stuck on a step? Read the free lesson: Solving Linear Equations
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