4MA1/1H Jun 2021, Question 16: Recurring Decimals
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1H (Higher) · Calculator · 2 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Using algebra, prove that the repeating decimal 0.28131313… equals 557/1980.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 2 marks
- 1Let x = 0.281313...
- 2100x = 28.1313...
- 310000x = 2813.1313...
- 410000x − 100x = 2813.1313... − 28.1313...
- 59900x = 2785
- 6x = 2785 / 9900
- 7x = 557 / 1980
Answer557/1980
Stuck on a step? Read the free lesson: Recurring Decimals
Practise more recurring decimals questions
Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on recurring decimals
Also searched as: 4MA1 1H June 2021 · 4MA1/1H · 4ma1 jun21 1h · question 16.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.