Lemmara logoLemmaraWorked solution

4MA1/1FR Jun 2025, Question 17: Upper and Lower Bounds

Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1FR (Foundation) · Calculator · 2 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

A ship's length is 142.8 m, given correct to 1 decimal place. State the lower bound and the upper bound of this length.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (i) · 1 mark

Write down the lower bound of the ship's length, given 142.8 m to 1 decimal place.

  1. 1Correct to 1 d.p. means ± 0.05
  2. 2142.8 − 0.05 = 142.75

Answer142.75

Part (ii) · 1 mark

Write down the upper bound of the ship's length, given 142.8 m to 1 decimal place.

  1. 1Correct to 1 d.p. means ± 0.05
  2. 2142.8 + 0.05 = 142.85

Answer142.85

Stuck on a step? Read the free lesson: Upper and Lower Bounds

Practise more upper and lower bounds questions

Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on upper and lower bounds

Also searched as: 4MA1 1FR June 2025 · 4MA1/1FR · 4ma1 jun25 1fr · question 17.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.