4PM1/01R Jan 2020, Question 10: Vector Geometry
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 1R · Calculator · 11 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Quadrilateral OABC has OA = 2a − b, OB = 3a + b and BC = −a + 3b. Work with vectors to find AB, show OC is parallel to AB, then find the ratio AX : XC where diagonals OB and AC meet at X.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 2 marks
Express the vector AB in terms of a and b, giving it in simplified form.
- 1AB = AO + OB = −(2a − b) + (3a + b)
- 2= a + 2b
AnswerAB = a + 2b
Part (b) · 2 marks
Show, using vectors, that OC and AB are parallel.
- 1OC = OB + BC = 3a + b − a + 3b = 2a + 4b
- 22a + 4b = 2(a + 2b) = 2AB
- 3OC is a positive multiple of AB, so they are parallel
AnswerOC = 2a + 4b = 2AB, so OC is parallel to AB
Part (c) · 7 marks
Using a vector method, determine the ratio in which X divides AC, i.e. AX : XC.
- 1AC = AB + BC = a + 2b − a + 3b = 5b
- 2AX = λAC = 5λb
- 3Also AX = AO + OX = −(2a − b) + μ(3a + b)
- 45λb = (3μ − 2)a + (1 + μ)b
- 5a: 3μ − 2 = 0, so μ = 2/3; b: 5λ = 1 + 2/3, so λ = 1/3
- 6AX : XC = 1 : 2
AnswerAX : XC = 1 : 2
Stuck on a step? Read the free lesson: Vector Geometry
Practise more vector geometry questions
Real 4PM1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on vector geometry
Also searched as: 4PM1 1R January 2020 · 4PM1/01R · 4pm1 jan20 1r · question 10.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.