4PM1/02 Jun 2019, Question 5: Hidden Quadratics and Harder Simultaneous Equations
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 6 marks
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The question, in short
Solve the simultaneous equations xy = 36 and xy + x + 2y = 53 using algebra.
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Solution · 6 marks
- 1Substitute xy = 36: x + 2y = 17
- 2x = 36/y: 36/y + 2y = 17
- 32y² − 17y + 36 = 0
- 4(y − 4)(2y − 9) = 0
- 5y = 4 → x = 9; y = 9/2 → x = 8
Answerx = 9, y = 4 or x = 8, y = 9/2
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