4PM1/01 Jun 2020, Question 1: The Product and Quotient Rules
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 1 · Calculator · 3 marks
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The question, in short
Differentiate 6e^(3x²) cos 2x with respect to x, using the product and chain rules.
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Solution · 3 marks
- 1Product rule with u = 6e^(3x²), v = cos 2x
- 2du/dx = 36xe^(3x²), dv/dx = −2sin 2x
- 3d/dx = 36xe^(3x²) cos 2x + 6e^(3x²) × (−2sin 2x)
- 4= 36xe^(3x²) cos 2x − 12e^(3x²) sin 2x
Answer36xe^(3x²) cos 2x − 12e^(3x²) sin 2x
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