4PM1/01 Jun 2025, Question 9: Stationary Points and Turning Points
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 1 · Calculator · 13 marks
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The question, in short
Given a cubic y = 2x³ + ax² + bx + c with a maximum at (−1/3, 100/27) and a minimum at (2, −9), find a, b, c, factorise, and find the shaded area.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 5 marks
Using the maximum and minimum points, determine the integer values of a, b and c in the cubic.
- 1f′(x) = 6x² + 2ax + b
- 2f′(2) = 0: 24 + 4a + b = 0
- 3f′(−1/3) = 0: 2/3 − 2a/3 + b = 0
- 4Solving: a = −5, b = −4
- 5f(2) = −9: 16 − 20 − 8 + c = −9, so c = 3
Answera = −5, b = −4, c = 3 shown
Part (bi) · 1 mark
Demonstrate that x + 1 divides the cubic.
- 1f(−1) = −2 − 5 + 4 + 3 = 0
- 2By the factor theorem, (x + 1) is a factor
Answerf(−1) = 0, so (x + 1) is a factor
Part (bii) · 3 marks
Fully factorise the cubic into linear factors using algebra.
- 1Divide by (x + 1): quotient 2x² − 7x + 3
- 22x² − 7x + 3 = (2x − 1)(x − 3)
- 3f(x) = (x + 1)(x − 3)(2x − 1)
Answerf(x) = (x + 1)(x − 3)(2x − 1)
Part (c) · 4 marks
Find the total area of both shaded regions between the curve and the x-axis, giving an exact fraction.
- 1M = −1, N = 1/2, P = 3
- 2∫ f(x) dx = x⁴/2 − (5/3)x³ − 2x² + 3x
- 3From −1 to 1/2: 117/32
- 4From 1/2 to 3: −1375/96, area 1375/96
- 5Total = 117/32 + 1375/96 = 863/48
Answer863/48
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