Lemmara logoLemmaraWorked solution

4PM1/02 Jun 2025, Question 1: Solving Trig Equations

Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 5 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

Solve √3 tan A = 2 sin A for A in the range 0° to 360°, giving all angles that satisfy the equation.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Solution · 5 marks

  1. 1√3 sin A/cos A = 2 sin A
  2. 2√3 sin A − 2 sin A cos A = 0
  3. 3sin A(√3 − 2cos A) = 0
  4. 4sin A = 0: A = 0°, 180°, 360°
  5. 5cos A = √3/2: A = 30°, 330°

AnswerA = 0°, 30°, 180°, 330°, 360°

Stuck on a step? Read the free lesson: Solving Trig Equations

Practise more solving trig equations questions

Real 4PM1 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on solving trig equations

Also searched as: 4PM1 2 June 2025 · 4PM1/02 · 4pm1 jun25 2 · question 1.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.