WMA11/01 Oct 2023, Question 8: Simultaneous Equations with a Curve
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 1 (WMA11) · Calculator · 7 marks
The question, in short
Show algebraically that curves C₁ (xy = 15/2 − 5x) and C₂ (y = x³ − (7/2)x − 5) intersect where 2x⁴ − 7x² − 15 = 0, then find the exact distance between intersection points P and Q.
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Part (a) · 2 marks
Show that substituting the equation of C₂ into C₁ leads to the quartic equation 2x⁴ − 7x² − 15 = 0.
- 1Substitute y from C₂ into C₁: x(x³ − (7/2)x − 5) = 15/2 − 5x
- 2x⁴ − (7/2)x² − 5x = 15/2 − 5x
- 3x⁴ − (7/2)x² − 15/2 = 0
- 4Multiply by 2: 2x⁴ − 7x² − 15 = 0
AnswerShown: x(x³ − (7/2)x − 5) = 15/2 − 5x ⇒ x⁴ − (7/2)x² = 15/2 ⇒ 2x⁴ − 7x² − 15 = 0
Part (b) · 5 marks
Using algebra, find the coordinates of P and Q and hence the exact distance PQ.
- 1Factorise as a quadratic in x²: (2x² + 3)(x² − 5) = 0
- 22x² = −3 has no real roots, so x² = 5 and x = ±√5
- 3y = 15/(2x) − 5: at x = √5, y = −5 + (3/2)√5; at x = −√5, y = −5 − (3/2)√5
- 4Differences: Δx = 2√5, Δy = 3√5
- 5PQ = √((2√5)² + (3√5)²) = √(20 + 45) = √65
AnswerPQ = √65
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