WMA12/01 Jun 2022, Question 6: Geometric Progressions and Sum to Infinity
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 2 (WMA12) · Calculator · 8 marks
The question, in short
Geometric sequence with common ratio r, u₂ + u₃ = 6 and u₄ = 8: show r satisfies 3r² − 4r − 4 = 0, then find u₁ and S∞ given a sum to infinity exists.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Using u₂ + u₃ = 6 and u₄ = 8, derive and show the quadratic equation 3r² − 4r − 4 = 0 for the common ratio r.
- 1Using uₙ = arⁿ⁻¹: ar + ar² = 6 and ar³ = 8
- 2Divide: (ar + ar²)/(ar³) = 6/8, so (1 + r)/r² = 3/4
- 34 + 4r = 3r²
- 43r² − 4r − 4 = 0
AnswerShown: (ar + ar²)/ar³ = 6/8 gives 1 + r = (3/4)r², so 3r² − 4r − 4 = 0
Part (b) · 3 marks
Given the sequence has a sum to infinity, find the first term u₁.
- 13r² − 4r − 4 = 0 gives (3r + 2)(r − 2) = 0, so r = −2/3 or r = 2
- 2A sum to infinity needs |r| < 1, so r = −2/3
- 3ar³ = 8, so a = 8/(−2/3)³ = 8/(−8/27)
- 4u₁ = −27
Answeru₁ = −27
Part (c) · 2 marks
Find S∞, the sum to infinity of the sequence.
- 1S∞ = a/(1 − r) = −27/(1 − (−2/3))
- 2= −27/(5/3) = −81/5
AnswerS∞ = −81/5
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