0580/22 Feb/Mar 2024, Question 26: The Perpendicular Bisector
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 5 marks
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The question, in short
Given points A (6, 1) and B (2, 7), find the perpendicular bisector of AB and express it as y = mx + c.
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Solution · 5 marks
- 1Midpoint of AB = ((6 + 2)/2, (1 + 7)/2) = (4, 4)
- 2Gradient of AB = (7 − 1)/(2 − 6) = −3/2
- 3Perpendicular gradient = 2/3
- 44 = 2/3 × 4 + c, so c = 4 − 8/3 = 4/3
- 5y = (2/3)x + 4/3
Answery = (2/3)x + 4/3
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Also searched as: 0580/22/F/M/24 · 0580_m24_qp_22 · 0580 m24 22 · question 26.
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