0580/22 Oct/Nov 2024, Question 22: The Perpendicular Bisector
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 5 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Given points A (17, 9) and B (23, 39), find the perpendicular bisector equation of AB in the form y = mx + c.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 5 marks
- 1Midpoint of AB = ((17 + 23)/2, (9 + 39)/2) = (20, 24)
- 2Gradient AB = (39 − 9)/(23 − 17) = 30/6 = 5
- 3Perpendicular gradient = −1/5
- 424 = −1/5 × 20 + c → c = 28
- 5y = −1/5 x + 28
Answer−1/5 x + 28
Stuck on a step? Read the free lesson: The Perpendicular Bisector
Practise more the perpendicular bisector questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on the perpendicular bisector
Also searched as: 0580/22/O/N/24 · 0580_w24_qp_22 · 0580 w24 22 · question 22.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.