0580/22 Feb/Mar 2025, Question 4: Substitution
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Non-calculator · 4 marks
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The question, in short
Use the formula V = 4mp² to evaluate V for given m and p, then find the positive p for given V and m.
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Part (a) · 2 marks
Substitute m = 10 and p = −3 into V = 4mp² and calculate V.
- 1V = 4 × 10 × (−3)²
- 2= 4 × 10 × 9 = 360
Answer360
Part (b) · 2 marks
Given V = 3200 and m = 2, solve V = 4mp² for the positive value of p.
- 13200 = 4 × 2 × p²
- 2p² = 3200 ÷ 8 = 400
- 3p = √400 = 20
Answer20
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Also searched as: 0580/22/F/M/25 · 0580_m25_qp_22 · 0580 m25 22 · question 4.
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