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0580/23 May/Jun 2026, Question 17: Rearranging Complex Formulas

Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Non-calculator · 6 marks

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The question, in short

Substitute a = −2 and b = 3 into c = 4a² + 2b to find c, then rearrange y = 2(x − 3)/(x − 5) to make x the subject.

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Part (a) · 2 marks

Work out c using c = 4a² + 2b with a = −2 and b = 3.

  1. 14 × (−2)² = 4 × 4 = 16
  2. 22 × 3 = 6
  3. 3c = 16 + 6 = 22

Answer22

Part (b) · 4 marks

Rearrange y = 2(x − 3)/(x − 5) so that x is expressed in terms of y.

  1. 1y(x − 5) = 2(x − 3)
  2. 2yx − 5y = 2x − 6
  3. 3yx − 2x = 5y − 6
  4. 4x(y − 2) = 5y − 6
  5. 5x = (5y − 6)/(y − 2)

Answer(5y − 6)/(y − 2)

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Also searched as: 0580/23/M/J/26 · 0580_s26_qp_23 · 0580 s26 23 · question 17.
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