0580/43 May/Jun 2021, Question 6: Conditional Probability
Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 9 marks
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The question, in short
Use the given counts for 24 students, 18 liking H, 15 liking T and 1 liking neither to complete a Venn diagram and answer related counting and probability questions.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 2 marks
Fill the three blank regions of the Venn diagram using the totals and the 1 outside both circles.
- 1In H or T: 24 − 1 = 23
- 2Both: 18 + 15 − 23 = 10
- 3H only: 18 − 10 = 8; T only: 15 − 10 = 5
- 4H only 8, H ∩ T 10, T only 5, outside 1
AnswerH only: 8 H ∩ T: 10 T only: 5 Outside H and T: 1
Part (b) · 1 mark
State how many students are in the overlap of homework and tests.
- 1From the Venn diagram, H ∩ T = 10
Answer10
Part (c) · 1 mark
Find the number of students in T only, that is outside H but inside T.
- 1H′ ∩ T is T only = 5
Answer5
Part (d) · 1 mark
Give the probability a randomly chosen student likes tests but not homework.
- 1T only = 5 out of 24 students
- 2P = 5/24
Answer5/24
Part (e) · 1 mark
Find the probability that two students chosen at random both like neither homework nor tests.
- 1Only 1 student likes neither
- 2P = 1/24 × 0/23 = 0
Answer0
Part (f) · 3 marks
Given two students who like homework are chosen, find the probability both also like tests.
- 110 of the 18 homework-likers also like tests
- 2P = 10/18 × 9/17 = 90/306
- 3= 5/17
Answer5/17
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Also searched as: 0580/43/M/J/21 · 0580_s21_qp_43 · 0580 s21 43 · question 6.
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