0580/31 May/Jun 2024, Question 2: Bar Charts and Composite Bar Charts
Cambridge IGCSE Mathematics 0580 · Paper 31 (Core) · Calculator · 15 marks
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The question, in short
Use a pie chart of holiday preferences with sector angles to find fractions, percentages, ratios and probabilities, complete a frequency table and bar chart, and compare holiday costs in euros using an exchange rate.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Find the fraction of people preferring a mountain holiday from its 120° sector, in simplest form.
- 1Mountain sector = 120°
- 2120/360 = 1/3
Answer1/3
Part (aii) · 1 mark
Find the percentage preferring a beach holiday from its 135° sector.
- 1Beach sector = 135°
- 2135/360 × 100 = 37.5%
Answer37.5
Part (aiii) · 2 marks
Write the ratio beach : cruise : lake : mountain using the sector angles, in simplest form.
- 1Angles beach : cruise : lake : mountain = 135 : 30 : 75 : 120
- 2Divide by 15: 9 : 2 : 5 : 8
Answer9 : 2 : 5 : 8
Part (aiv) · 2 marks
Find the probability a randomly chosen person prefers cruise or lake.
- 1Cruise + lake = 30° + 75° = 105°
- 2P = 105/360 = 7/24
Answer105/360 or 7/24
Part (av) · 1 mark
Given 675 people prefer beach, show the total number asked is 1800.
- 1Beach sector 135° represents 675 people
- 21° represents 675 ÷ 135 = 5 people
- 3Total = 5 × 360 = 1800
Answer675 × 360 / 135 = 1800
Part (avia) · 2 marks
Complete the frequency column for Lake and Mountain using the sector angles.
- 11° represents 1800 ÷ 360 = 5 people
- 2Lake = 75 × 5 = 375
- 3Mountain = 120 × 5 = 600
AnswerLake 375, Mountain 600
Part (avib) · 3 marks
Complete the bar chart for all four holidays, including a suitable scale on the frequency axis.
- 1Choose a linear scale, e.g. 0, 100, 200, …, 700
- 2Draw bars to heights Beach 675, Cruise 150
- 3Lake 375, Mountain 600
AnswerCorrect bar chart with linear scale labelled: Beach 675, Cruise 150, Lake 375, Mountain 600
Part (b) · 2 marks
Work out how many more euros Mr Shah pays than Mr Gibb, given $2208 and 2050 euros at 1 euro = $1.15.
- 1Mr Gibb in euros = 2208 ÷ 1.15 = 1920
- 22050 − 1920 = 130 euros
Answer130
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Also searched as: 0580/31/M/J/24 · 0580_s24_qp_31 · 0580 s24 31 · question 2.
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