0580/21 May/Jun 2025, Question 14: Algebraic Fractions
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Non-calculator · 8 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Given f(x) = 3x − 4 and g(x) = 4x + 1, evaluate f at −2, find the inverse of f, find a and b in fg(x) = ax + b, and combine 2/f(x) − 5/g(x) into one fraction.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Work out f(−2) using f(x) = 3x − 4.
- 1f(−2) = 3 × (−2) − 4 = −10
Answer−10
Part (b) · 2 marks
Find the inverse function f⁻¹(x) for f(x) = 3x − 4.
- 1y = 3x − 4, so y + 4 = 3x
- 2x = (y + 4)/3
- 3f⁻¹(x) = (x + 4)/3
Answer(x + 4)/3
Part (c) · 2 marks
Given fg(x) = ax + b, find the values of a and b.
- 1fg(x) = 3(4x + 1) − 4
- 2= 12x + 3 − 4 = 12x − 1
- 3a = 12, b = −1
Answera = 12, b = −1
Part (d) · 3 marks
Simplify 2/f(x) − 5/g(x) to a single fraction in x.
- 12/(3x − 4) − 5/(4x + 1)
- 2= [2(4x + 1) − 5(3x − 4)]/((3x − 4)(4x + 1))
- 3= (8x + 2 − 15x + 20)/((3x − 4)(4x + 1))
- 4= (22 − 7x)/((3x − 4)(4x + 1))
Answer(22 − 7x)/((3x − 4)(4x + 1)) or (22 − 7x)/(12x² − 13x − 4)
Stuck on a step? Read the free lesson: Algebraic Fractions
Practise more algebraic fractions questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on algebraic fractions
Also searched as: 0580/21/M/J/25 · 0580_s25_qp_21 · 0580 s25 21 · question 14.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.