0580/32 May/Jun 2025, Question 14: Substitution
Cambridge IGCSE Mathematics 0580 · Paper 32 (Core) · Calculator · 4 marks
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The question, in short
Given P = 6a + 5b, find b for P = 25 and a = 3, then rearrange W = kT + y to make T the subject.
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Part (a) · 2 marks
Substitute P = 25 and a = 3 into P = 6a + 5b and find the value of b.
- 125 = 6 × 3 + 5b
- 225 = 18 + 5b
- 35b = 7
- 4b = 7 ÷ 5 = 1.4
Answer1.4
Part (b) · 2 marks
Rearrange the formula W = kT + y so that T is the subject.
- 1W − y = kT
- 2T = (W − y)/k
Answer(W − y)/k or W/k − y/k
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Also searched as: 0580/32/M/J/25 · 0580_s25_qp_32 · 0580 s25 32 · question 14.
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