0580/21 May/Jun 2026, Question 15: Area of a Sector
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Non-calculator · 4 marks
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The question, in short
Compare the areas of a quarter circle of radius t cm and a 135° sector of radius 2t cm, and find the multiplier k relating the sector's area to the quarter circle's area.
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Solution · 4 marks
- 1Area A = 90/360 × πt² = 1/4 πt²
- 2Area B = 135/360 × π(2t)² = 3/8 × 4πt² = 3/2 πt²
- 3k = (3/2 πt²) ÷ (1/4 πt²)
- 4k = 3/2 × 4 = 6
Answer6
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Also searched as: 0580/21/M/J/26 · 0580_s26_qp_21 · 0580 s26 21 · question 15.
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