0580/32 May/Jun 2026, Question 26: Using Trigonometry and Pythagoras Together
Cambridge IGCSE Mathematics 0580 · Paper 32 (Core) · Calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Right-angled triangle PQR with S on PR, QS = 23 cm, angle PQS = 31° and angle RQS = 44°; calculate the length PR.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 4 marks
- 1In triangle QRS: QR = 23 × cos44° = 16.545 cm
- 2Angle PQR = 31° + 44° = 75°
- 3PR = QR × tan75°
- 4= 16.545 × 3.732 = 61.7 cm
Answer61.7 or 61.74 to 61.75
Stuck on a step? Read the free lesson: Using Trigonometry and Pythagoras Together
Practise more using trigonometry and pythagoras together questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on using trigonometry and pythagoras together
Also searched as: 0580/32/M/J/26 · 0580_s26_qp_32 · 0580 s26 32 · question 26.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.